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> AdviceSpring stiffnesses for joints assigned between linesA spring stiffness is sometimes required in the definition of a joint
assigned between line features, or a support attribute assigned to a line
feature in LUSAS. Spring stiffness, k, is as defined in Hooke's law, viz. F=k*x where F is an applied force and x is the resulting displacement.  It follows that where a
known displacement (x) for a known force (F) is available, the spring stiffness entered in the dialog box, k = F/x (typical units
kN/m, N/mm etc). 
When assigned to line features, which have a length, forces are
per unit length and spring stiffnesses should be likewise (typical units therefore
kN/m², N/mm² etc). Engineering theory can be used to derive equations for k based on the structural member which the spring is intended to model e.g. If we assume the supporting
member to behave as a 2D continuum: 
          Perpendicular to joint:   Kx = EA/l      based on in-plane ("axial") deformation.  Since Kx will
          normally be defined "per  unit length" and assigned to a
          line feature, in the usual way A=thickness, t. Parallel to joint:  Ky = Gt/L      based on shear deformation.  For isotropic elastic materials,  Shear modulus G=E/[2(1+v)].  Parallel to joint: Kz = 3EI/l³    based on flexural deformation of slab (minor bending axis).   Since
          Kz will normally be "per  unit length" and assigned to a
          line feature, in the usual way 't' should be divided through. Sometimes it is necessary to use a joint element to model a "fixed"
or "free" condition (e.g. to mimic the action of a tension-only member).  
However: 
            For a "fixed" condition, you cannot enter a stiffness of infinity, so you should use a high stiffness.For a "free" condition, you may not be able to enter a stiffness of zero, so you may use a low stiffness.  Zero may be entered but may cause numerical instability, depending on the solution method selected. In a case where the stiffness specified is to model a "fixed" or
"free" condition, in principle, the stiffnesses should be high or low relative
to the rest of the structure, in particular adjacent members. A good starting point for the estimation of a suitable spring stiffness
might therefore be:  
            For a "fixed" condition, input spring
              stiffnesses:Perpendicular:      Kx = 1000*Et/l, Parallel: Ky = 1000*Gt/L,
              Lateral: Kz = 1000*3EI/tl³
 based on the most stiff adjacent element
For a "free" condition, input spring
              stiffnesses:Perpendicular:      Kx = 0.001*Et/l, Parallel: Ky = 0.001*Gt/L,
              Lateral: Kz = 0.001*3EI/tl³
 based on the least stiff adjacent element
 
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